The electric field in a certain region is act | vedclass

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Question

According to question, electric field varies as

$E=A r$

Here $r$ is the radial distance.

At $r=a, E=A a.........(i)$

Net flux emitted from

Vedclass · Accepted Answer

$\;4\pi {\varepsilon _0}A{a^3}$

Vedclass · Answer

According to question, electric field varies as

$E=A r$

Here $r$ is the radial distance.

At $r=a, E=A a.........(i)$

Net flux emitted from a spherical surface of radius $a$ is $\phi_{\mathrm{net}}=\frac{q_{e n}}{\varepsilon_{0}}$

$\Rightarrow \quad(A a) 	imes\left(4 \pi a^{2}ight)=\frac{q}{\varepsilon_{0}} \quad[	ext { Using equation }(\mathrm{i})]$

$	herefore \quad q=4 \pi \varepsilon_{0} A a^{3}$

The electric field in a certain region is acting radially outward and is given by $E =Ar.$ A charge contained in a sphere of radius $'a'$ centred at the origin of the field, will be given by

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