The energy and capacity of a charged parallel plate capacitor are $U$ and $C$ respectively. Now a dielectric slab of $\in _r = 6$ is inserted in it then energy and capacity becomes  (Assume charge on plates remains constant)

  • A

    $6\,U,\, 6\,C$

  • B

    $U,\, C$

  • C

    $\frac{U}{6}\,,6C$

  • D

    $U,\, 6\,C$

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  • [AIIMS 2019]