Energy of a photon of wavelength λ is given by

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11.Dual Nature of Radiation and matter

easy

The energy of a photon of wavelength $\lambda $ is given by

A

$h\lambda $

B

$ch\lambda $

C

$\lambda /hc$

D

$hc/\lambda $

(AIPMT-1988)

Solution

The energy of a photon is directly proportional to its frequency with proportionality constant being the Plank's constant $h$

Hence $E=h \nu=h \frac{c}{\lambda}(\text { since } c=\lambda \nu)$

$\Longrightarrow E=\frac{h c}{\lambda}$

Standard 12

Physics

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