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14.Waves and Sound
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The equation of transverse wave in stretched string is $y = 5\,\sin \,2\pi \left[ {\frac{t}{{0.04}} - \frac{x}{{50}}} \right]$ Where distances are in cm and time in second. The wavelength of wave is .... $cm$
A
$15$
B
$10$
C
$25$
D
$50$
Solution
$k = \frac{{2\pi }}{\lambda } = \frac{{2\pi }}{{50}}\,\,or\,\,\lambda = 50\,cm$
Standard 11
Physics
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