Gujarati
Hindi
14.Waves and Sound
normal

The equation of transverse wave in stretched string is $y = 5\,\sin \,2\pi \left[ {\frac{t}{{0.04}} - \frac{x}{{50}}} \right]$ Where distances are in cm and time in second. The wavelength of wave is .... $cm$

A

$15$

B

$10$

C

$25$

D

$50$

Solution

$k = \frac{{2\pi }}{\lambda } = \frac{{2\pi }}{{50}}\,\,or\,\,\lambda  = 50\,cm$

Standard 11
Physics

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