The equivalent capacitance between points $A$ and $B$ of the circuit shown will be
The equivalent capacitance between points $A$ and $B$ of the circuit shown will be
- A
$\frac{2}{3} \, \mu F$
- B
$\frac{5}{3} \, \mu F$
- C
$\frac{8}{3} \, \mu F$
- D
$\frac{7}{3} \, \mu F$
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