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14.Waves and Sound
easy
The first overtone of a stretched wire of given length is $320 Hz$. The first harmonic is .... $Hz$
A
$320$
B
$160$
C
$480$
D
$640$
Solution
(b) Frequency of first overtone or second harmonic $(n_2) = 320\,Hz$.
So, frequency of first harmonic ${n_1} = \frac{{{n_2}}}{2} = \frac{{320}}{2} = 160Hz$
Standard 11
Physics
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