14.Waves and Sound
easy

The first overtone of a stretched wire of given length is $320 Hz$. The first harmonic is  .... $Hz$

A

$320$

B

$160$

C

$480$

D

$640$

Solution

(b) Frequency of first overtone or second harmonic $(n_2)  = 320\,Hz$.

So, frequency of first harmonic ${n_1} = \frac{{{n_2}}}{2} = \frac{{320}}{2} = 160Hz$

Standard 11
Physics

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