Two monoatomic ideal gas at temperature $T_1$ and $T_2$ are mixed. There is no loss of energy. If the masses of molecules of the two gases are $m_1$ and $m_2$ and number of their molecules are $n_1$ and $n_2$ respectively. The temperature of the mixture will be :

Two spherical vessel of equal volume, are connected by a n arrow tube. The apparatus contains an ideal gas at one atmosphere and $300K$. Now if one vessel is immersed in a bath of constant temperature $600K$ and the other in a bath of constant temperature $300K$. Then the common pressure will be …… $atm$

An ideal gas follows a process $PT =$ constant. The correct graph between pressure & volume is

Two identical containers $A$ and $B$ with frictionless pistons contain the ideal gas at the same temperature and the same volume $V$. The mass of the gas in $A$ is $m_A$ and in $B$ is $m_B$. The gas in each cylinder is now allowed to expand isothermally to the same final volume $2V$. The changes in pressure in $A$ and $B$ are found to be $\Delta p$ and $1.5\Delta P$ respectively. Then

If $C_p$ and $C_v$ denote the specific heat of nitrogen at constant pressure and constant volume respectiely, then