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4.Average
hard
The frequency distribution date is given below. If the average age is $17\, years,$ the value of $m$ is Age
| Age (in $years$) | : | 8 | 20 | 26 | 29 |
| Number of People | : | 3 | 2 | m | 1 |
A
$1$
B
$2$
C
$3$
D
$4$
Solution
Required average
$=\frac{8 \times 3+20 \times 2+26 \times m+29 \times 1}{3+2+m+1}$
$\Rightarrow 17=\frac{24+40+26 m+29}{6+m}$
$\Rightarrow 17(6+m)=93+26 m$
$\Rightarrow 102+17 m)=93+26 m$
$\Rightarrow 26 m-17 m=102-93$
$\Rightarrow 9 m=9 \Rightarrow m=1$
Standard 13
Quantitative Aptitude
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