- Home
- Standard 12
- Biology
4.Principles of Inheritance and Variation
medium
The genotypes of a husband and wife are $I^AI^B$ and $I^Ai$. Among the blood types of their children, how many different genotypes and phenotypes are possible?
A
$3$ genotypes; $4$ phenotypes
B
$4$ genotypes; $3$ phenotypes
C
$4$ genotypes; $4$ phenotypes
D
$3$ genotypes; $3$ phenotypes
(NEET-2017)
Solution
(b): If the genotypes of husband and wife are $I^AI^B$ and $I^Ai$ respectively, then the probabilities of genotypes and phenotypes among their children can be worked out as:
Genotype: | $I^A I^A$ | $ I^Ai$ | $ I^AI^B$ | $I^Bi$ |
Phenotype: | $A$ | $A$ | $AB$ | $B$ |
Thus, there are four possible genotypes, viz., $I^AI^A, I^Ai, I^AI^B$ and $I^Bi$ and three possible phenotypes, viz., $A, AB$ and $B$ among the children.
Standard 12
Biology