The graph given below is the distance$-$time graph of an object.
$(i)$ Find the speed of the object during first four seconds of its journey.
$(ii)$ How long was it stationary ?
$(iii)$ Does it represent a real situation ? Justify your answer.
$(i)$ $OP$ indicates uniform speed given
$v=\frac{75-0}{4-0}=\frac{75}{4}=18.75 m s ^{-1}$
$(ii)$ $PQ$ is parallel to the time axis. It indicates that the object is stationary. It is a real situation.
$(iii)$ $QR$ shows that distance and time decreases, which is not possible. Thus, this is not a real situation.
A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement-time graph is shown in Fig. Plot a velocity - time graph for the same.
What is the slope of the displacement $-$ time graph when the body has uniform motion ?
$(a)$ Differentiate between distance and displacement.
$(b)$ Under what conditions is the magnitude of average velocity of an object equal to its average speed ?
Using following data, draw time-displacement graph for a moving object :
Time $(s)$ | $0$ | $2$ | $4$ | $6$ | $8$ | $10$ | $12$ | $14$ | $16$ |
Displacement $(m)$ | $0$ | $2$ | $4$ | $4$ | $4$ | $6$ | $4$ | $2$ | $0$ |
Use this graph to find average velocity for first $4\,\sec $, for next $4\,\sec $ and for last $6\,\sec $.
A car is moving on a straight road with uniform acceleration. The following table gives the speed of the car at various instants of time.
Time $(s)$ | $0$ | $10$ | $20$ | $30$ | $40$ | $50$ |
Speed $\left(m s^{-1}\right)$ | $5$ | $10$ | $15$ | $20$ | $25$ | $30$ |
$(i)$ Draw the speed$-$time graph representing the above set of observations.
$(ii)$ Find the acceleration of the car.