The graph given below is the distance$-$time graph of an object.

$(i)$ Find the speed of the object during first four seconds of its journey.

$(ii)$ How long was it stationary ?

$(iii)$ Does it represent a real situation ? Justify your answer.

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$(i)$ $OP$ indicates uniform speed given

$v=\frac{75-0}{4-0}=\frac{75}{4}=18.75 m s ^{-1}$

$(ii)$ $PQ$ is parallel to the time axis. It indicates that the object is stationary. It is a real situation.

$(iii)$ $QR$ shows that distance and time decreases, which is not possible. Thus, this is not a real situation.

Similar Questions

A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement-time graph is shown in Fig. Plot a velocity - time graph for the same.

What is the slope of the displacement $-$ time graph when the body has uniform motion ?

$(a)$ Differentiate between distance and displacement.

$(b)$ Under what conditions is the magnitude of average velocity of an object equal to its average speed ?

Using following data, draw time-displacement graph for a moving object :

Time $(s)$ $0$ $2$ $4$ $6$ $8$ $10$ $12$ $14$ $16$
Displacement $(m)$ $0$ $2$ $4$ $4$ $4$ $6$ $4$ $2$ $0$

Use this graph to find average velocity for first $4\,\sec $, for next $4\,\sec $ and for last $6\,\sec $.

A car is moving on a straight road with uniform acceleration. The following table gives the speed of the car at various instants of time.

Time $(s)$ $0$ $10$ $20$ $30$ $40$ $50$
Speed $\left(m s^{-1}\right)$ $5$ $10$ $15$ $20$ $25$ $30$

$(i)$ Draw the speed$-$time graph representing the above set of observations.

$(ii)$ Find the acceleration of the car.