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7. MOTION
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The graph given below is the distance$-$time graph of an object.
$(i)$ Find the speed of the object during first four seconds of its journey.
$(ii)$ How long was it stationary ?
$(iii)$ Does it represent a real situation ? Justify your answer.
Option A
Option B
Option C
Option D
Solution
$(i)$ $OP$ indicates uniform speed given
$v=\frac{75-0}{4-0}=\frac{75}{4}=18.75 m s ^{-1}$
$(ii)$ $PQ$ is parallel to the time axis. It indicates that the object is stationary. It is a real situation.
$(iii)$ $QR$ shows that distance and time decreases, which is not possible. Thus, this is not a real situation.
Standard 9
Science
