Graph of linear equation 2 x+3 y=6 cuts y -axis at point

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4. Linear Equations in Two Variables

easy

The graph of the linear equation $2 x+3 y=6$ cuts the $y$ -axis at the point

A

$(0,2)$

B

$(0,3)$

C

$(3,0)$

D

$(2,0)$

Solution

The graph of the linear equation $2 x+3 y=6$ cuts the $y$ -axis at the point where $x-$ coordinate is zero.

Putting $x=0$ in $2 x+3 y=6,$ we get

$2(0)+3 y=6 \Rightarrow 3 y=6 \Rightarrow y=6 \div 3=2$

So, $(0,2)$ is the required point.

Standard 9

Mathematics

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