- Home
- Standard 11
- Physics
10-1.Thermometry, Thermal Expansion and Calorimetry
medium
The graph shown in the figure represent change in the temperature of $5 \,\,kg$ of a substance as it abosrbs heat at a constant rate of $42 \,\,kJ min^{-1}$. The latent heat of vapourazation of the substance is ......... $kJ \,kg^{-1}$
A
$630$
B
$126$
C
$84$
D
$12.6$
Solution
First mass will melt and then vaporize, we can see there is a constant temperature line at $T=125^{\circ} C,$ that is its vaporization temperature, and heat supplied during that duration is latent heat of vaporization.
Heat absorbed is $42 \times(35-25)=5 \times L$
so, $L=84 k J / k g$
Standard 11
Physics
