Gujarati
13.Nuclei
medium

The half-life of radon is $3.8\, days$. Three forth of a radon sample decay in  ............$days$

A

$5.02$

B

$15.2 $

C

$7.6 $

D

$11.4$

Solution

(c) Decayed fraction $ = \frac{3}{4}$, so undecayed fraction $ = \frac{1}{4}$

Now $\frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^n}$

$\Rightarrow \frac{1}{4} = {\left( {\frac{1}{2}} \right)^n} \Rightarrow n = 2$

==> $t = n \times {T_{1/2}} = 2 \times 3.8 = 7.6\;days$

Standard 12
Physics

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