Gujarati
Hindi
7.Gravitation
medium

The height at which the weight of the body become $\frac{1}{9}^{th}$. Its weight on the surface of earth (radius of earth $R$)

A

$h = 3R$

B

$h = R$

C

$h = \frac{R}{2}$

D

$h = 2R$

Solution

$\mathrm{g}^{\prime}=\frac{\mathrm{g}}{\left(1+\frac{\mathrm{h}}{\mathrm{R}}\right)^{2}}=\mathrm{g}^{\prime}=\frac{\mathrm{g}}{9}$

$\frac{\mathrm{g}}{9}=\frac{\mathrm{g}}{\left(1+\frac{\mathrm{h}}{\mathrm{R}}\right)^{2}} \Rightarrow 1+\frac{\mathrm{h}}{\mathrm{R}}=3$

$\quad \mathrm{h}=2 \mathrm{R}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.