Gujarati
10-1.Thermometry, Thermal Expansion and Calorimetry
medium

The height of a waterfall is $84$ metre. Assuming that the entire kinetic energy of falling water is converted into heat, the rise in temperature of the water will be  $(g = 9.8\,m/{s^2},\;J = 4.2\,joule/cal)$

A

$0.196°C$

B

$1.960°C$

C

$0.96°C$

D

$0.0196°C$

Solution

(a) $W = JQ$ $\Rightarrow$ $mg\,h = J(m.c.\Delta \theta )$

$\Rightarrow$ $\Delta \theta = \frac{{g\,h}}{{Jc}} = 0.0023\,h = 0.0023 \times 84 = 0.196^\circ C$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.