Interatomic distance for a metal is 3 × {10^{ - 10}},m . If interatomic force constant is 3.6 × {1

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8.Mechanical Properties of Solids

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The interatomic distance for a metal is $3 \times {10^{ - 10}}\,m$. If the interatomic force constant is $3.6 \times {10^{ - 9}}\,N/{{\buildrel _{\circ} \over {\mathrm{A}}}}$, then the Young's modulus in $N/{m^2}$ will be

A

$1.2 \times {10^{11}}$

B

$4.2 \times {10^{11}}$

C

$10.8 \times {10^{ - 19}}$

D

$2.4 \times {10^{10}}$

Solution

(a) $Y = \frac{{3.6 \times {{10}^{ – 9}}N/\mathop A\limits^o }}{{3 \times {{10}^{ – 10}}m}}$$ = 1.2 \times {10^{11}}N/{m^2}$

Standard 11

Physics

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