Gujarati
4.Principles of Inheritance and Variation
medium

The map distance between genes $A$ and $B$ is $3$ units, between $B$ and $C$ $10$ units and between $C$ and $A$ $7$ units. The order of the genes in a linkage map constructed on the above data would perhaps be

A

$A, B, C$

B

$A, C, B$

C

$B, C, A$

D

$B, A, C$

Solution

(d) From the recombination frequencies between different genes $A, B$ and $C$, it is clear that distance between $A$ and $B$ genes is $3$ units, between $B$ and $C$ $10$ units and $C$ and $A$ $7$ units. Hence linear order of genes on chromosomes is :

Standard 12
Biology

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