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4.Principles of Inheritance and Variation
medium
The map distance between genes $A$ and $B$ is $3$ units, between $B$ and $C$ $10$ units and between $C$ and $A$ $7$ units. The order of the genes in a linkage map constructed on the above data would perhaps be
A
$A, B, C$
B
$A, C, B$
C
$B, C, A$
D
$B, A, C$
Solution
(d) From the recombination frequencies between different genes $A, B$ and $C$, it is clear that distance between $A$ and $B$ genes is $3$ units, between $B$ and $C$ $10$ units and $C$ and $A$ $7$ units. Hence linear order of genes on chromosomes is :
Standard 12
Biology
