Maximum acceleration of 5, kg block ...... m/s^2

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4-2.Friction

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The maximum acceleration of $5\, kg$ block ...... $m/s^2$

A

$1$

B

$3$

C

$0$

D

None

Solution

From $FBD$ of $5\, kg$ mass,

Friction force to the right due to $F$ is $f_{1}=0.1 \times 10 \times 10=10 N$

Friction force to the left due to $F$ is $f_{1}=0.1 \times(10+5) \times 10=45 N$

As $10 \mathrm{N}<45 \mathrm{N},$ the $5 \mathrm{kg}$ block will not move.

Therefore its acceleration is $0 m / s^{2}$

Standard 11

Physics

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