Gujarati
Hindi
10-2.Transmission of Heat
normal

The maximum energy in the thermal radiation from a hot source occurs at a wavelength of $11\times10^{-5}\, cm$. According to Wien's law, the temperature of the source (on kelvin scale) will be n times the temperature of another source (on Kelvin scale) for which the wavelength at maximum energy is $5.5\times10^{-5}\, cm$. The value of $n$ is

A

$2$

B

$4$

C

$0.5$

D

$1$

Solution

$\lambda_{1} \mathrm{T}_{1}=\lambda_{2} \mathrm{T}_{2}$

Given $\mathrm{T}_{1}=\mathrm{nT}_{2}$

$\lambda_{1} \mathrm{nT}_{2}=\lambda_{2} \mathrm{T}_{2}$

$\Rightarrow n=\frac{\lambda_{2}}{\lambda_{1}}=\frac{5.5 \times 10^{5}}{11 \times 10^{5}}=\frac{1}{2}$

Standard 11
Physics

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