8.Mechanical Properties of Solids
medium

The mean distance between the atoms of iron is $3 \times {10^{ - 10}}m$ and interatomic force constant for iron is $7\,N\,/m$The Young’s modulus of elasticity for iron is

A

$2.33 \times {10^5}\,N/{m^2}$

B

$23.3 \times {10^{10}}\,N/{m^2}$

C

$233 \times {10^{10}}\,N/{m^2}$

D

$2.33 \times {10^{10}}\,N/{m^2}$

Solution

(d)$Y = \frac{k}{{{r_0}}} = \frac{7}{{3 \times {{10}^{ – 10}}}} = 2.33 \times {10^{10}}N/{m^2}$

Standard 11
Physics

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