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8.Mechanical Properties of Solids
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The mean distance between the atoms of iron is $3 \times {10^{ - 10}}m$ and interatomic force constant for iron is $7\,N\,/m$The Young’s modulus of elasticity for iron is
A
$2.33 \times {10^5}\,N/{m^2}$
B
$23.3 \times {10^{10}}\,N/{m^2}$
C
$233 \times {10^{10}}\,N/{m^2}$
D
$2.33 \times {10^{10}}\,N/{m^2}$
Solution
(d)$Y = \frac{k}{{{r_0}}} = \frac{7}{{3 \times {{10}^{ – 10}}}} = 2.33 \times {10^{10}}N/{m^2}$
Standard 11
Physics
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