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12.Kinetic Theory of Gases
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The mean free path of a molecule of He gas is $\alpha$. Its mean free path along any arbitrary coordinate axis will be ...........
A
$\alpha$
B
$\frac{\alpha}{3}$
C
$\frac{\alpha}{\sqrt{3}}$
D
$3 \alpha$
Solution
(c)
Mean free path of a molecule is the resultant of path along three separate axis and they will be equal.
So, $\quad \alpha=\sqrt{\alpha_x^2+\alpha_y^2+\alpha_2^2}$
where $\alpha_x=\alpha_y^2 \alpha_2=$ (say) a
$\alpha=\sqrt{a^2+a^2+a^2}$
$\text { or } \quad a=\frac{\alpha}{\sqrt{3}}$
Standard 11
Physics
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