Gujarati
Hindi
12.Kinetic Theory of Gases
normal

The mean kinetic energy of $1\, mole$ of gas per degree of freedom (on the basis of kinetic theory of gases) is

A

$\frac{1}{2}\,kT$

B

$\frac{3}{2}\,kT$

C

$\frac{3}{2}\,RT$

D

$\frac{1}{2}\,RT$

Solution

$\frac{1}{2} k T \times N=\frac{1}{2} R T$

Standard 11
Physics

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