Mean of 50 observations was 36 . It was found later that an observation 48 was wrongly taken as 23 .

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The mean of $50$ observations was $36 .$ It was found later that an observation $48$ was wrongly taken as $23 .$ The corrected new mean is

A

$35.2$

B

$36.1$

C

$36.5$

D

$39.1$

Solution

Corrected new mean $=\frac{50 \times 36-23+48}{50}=36+\frac{25}{50}=36.5$

Standard 13

Quantitative Aptitude

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