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4.Average
medium
The mean of $100$ items was $46 .$ Later on it was discovered that an item $16$ was misread as $61$ and another item $43$ was misread as $34 .$ It was also found that the number of items twas $90$ and not $100 .$ Then what is the correct mean?
A
$50$
B
$50.7$
C
$52$
D
$52.7$
Solution
Required Average
$=\frac{100 \times 46-61-34+16+43}{90}$
$=\frac{4600-36}{90}=\frac{4564}{90}$
$=50.7$
Standard 13
Quantitative Aptitude