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3.Current Electricity
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The meter bridge shown is in balanced position with $\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{l}_{1}}{\mathrm{l}_{2}}$. If we now litterchange the positions of gavanometer and cell, will the bridge work? If yes, what will be balance condition?
A
yes, $\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{l}_{2}-\mathrm{l}_{1}}{\mathrm{l}_{2}+\mathrm{l}_{1}}$
B
no, no null point
C
yes, $\frac{P}{Q}=\frac{l_{2}}{l_{1}}$
D
yes, $\frac{P}{Q}=\frac{l_{1}}{l_{2}}$
(NEET-2019)
Solution
Interchanging cell and galvanometer do not effect balance condition.
Standard 12
Physics
