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4.Chemical Bonding and Molecular Structure
easy
The molecular electronic configuration of $H_2^ - $ ion is
A
${\left( {\sigma \,1s} \right)^2}$
B
${\left( {\sigma \,1s} \right)^2}{\left( {{\sigma ^*}1s} \right)^2}$
C
${\left( {\sigma \,1s} \right)^2}{\left( {{\sigma ^*}1s} \right)^1}$
D
${\left( {\sigma \,1s} \right)^3}$
Solution
Total number of electrons in $H _2^{-}$are $3$ so, we can assume that the $H _2^{-}$ molecule is formed by the combination of $H$ and $H ^{-}$ atoms. Therefore, electronic configuration is $1 s ^2 * 1 s ^1$.
Standard 11
Chemistry
