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General Principles and processes of Isolation of Elements
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The oxide of a metal $(R)$ can be reduced by the metal $(P)$ and metal $(R)$ can reduce the oxide of metal $(Q)$. Then the decreasing order of the reactivity of metal $(P),\,(Q)$ and $(R)$ with oxygen is
A
$P >Q>R$
B
$P >R>Q$
C
$R > P > Q$
D
$Q > P > R$
Solution
As $R$ can reduce oxide of $Q$, so $R$ is more reactive than $Q$.
$P$ can reduce oxide of $R$ so $P$ is more reactive than $R$.
So, reactivity order is $P\, >\, R \,>\, Q$.
Standard 12
Chemistry
