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4.Chemical Bonding and Molecular Structure
medium
The paramagnetic property of the oxygen molecule due to the presence of unpaired electorns present in
A
${(\sigma 2{p_x})^1}$ and ${({\sigma ^*}2{p_x})^1}$
B
${(\sigma 2{p_x})^1}$ and ${(\pi 2{p_y})^1}$
C
${(\pi^*2{p_y})^1}$ and ${(\pi^*2{p_z})^1}$
D
${(\pi^*2{p_y})^1}$ and ${(\pi 2{p_y})^1}$
Solution
(c) The paramagnetic property in oxygen came through unpaired electron which can be explained by molecular orbital theory.
So $2$ unpaired of electron present in $\pi \;2p_y^*\;{\text{and}}\;\pi \;2p_z^*$
Standard 11
Chemistry
