Population of a town increases by 5 % every year. If present population is 9261, population 3 years

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6.Interest

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The population of a town increases by $5 \%$ every year. If the present population is $9261,$ the population $3$ $years$ ago was

A

$5700$

B

$6000$

C

$7500$

D

$8000$

Solution

(d) Percentage increase $5 \%$ Population of town 3 years ago $=\frac{926^{\prime}}{\gamma 0 \%} / F$

$\begin{aligned} 9261 &=P\left(1+\frac{r}{100}\right)^{n} \\ 9261 &=P\left(1+\frac{5}{100}\right)^{3} \\ 9261 &=P(1.157) \\ P &=8000 \end{aligned}$

Standard 13

Quantitative Aptitude

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