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6.System of Particles and Rotational Motion
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The position of a particle is given by $\overrightarrow r = (\overrightarrow i + 2\overrightarrow j - \overrightarrow k )$ momentum $\overrightarrow P = (3\overrightarrow i + 4\overrightarrow j - 2\overrightarrow k ).$ The angular momentum is perpendicular to
A$x-axis$
B$y-axis$
C$z-axis$
DLine at equal angles to all the three axes
Solution
(a) $\vec L = \vec r \times \vec p = \left| {\,\begin{array}{*{20}{c}}{\hat i}&{\hat j}&{\hat k}\\1&2&{ – 1}\\3&4&{ – 2}\end{array}\,} \right|$$ = – \hat j – 2\hat k$
i.e. the angular momentum is perpendicular to $x-$axis.
i.e. the angular momentum is perpendicular to $x-$axis.
Standard 11
Physics
