Position of a particle moving along x -axis is given by x=10 t-2 t^2 . Then time (t) at which it wil

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2.Motion in Straight Line

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The position of a particle moving along $x$-axis is given by $x=10 t-2 t^2$. Then the time $(t)$ at which it will momently come to rest is .......... $s$

A

$0$

B

$2.5$

C

$5$

D

$10$

Solution

(b)

$x=10 t-2 t^2$

$v=\frac{d x}{d t}=10-4 t$

$v=0$, at the time of coming to rest, so

$10-4 t=0$

$t=2.5 \,s$

Standard 11

Physics

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