The position of a projectile launched from the origin at $t = 0$ is given by $\vec r = \left( {40\hat i + 50\hat j} \right)\,m$ at $t = 2\,s$. If the projectile was launched at an angle $\theta$ from the horizontal, then $\theta$ is (take $g = 10\, ms^{-2}$)

Two projectiles are thrown simultaneously in the same plane from the same point. If their velocities are $v_1$ and $v_2$ at angles $\theta _1$ and $\theta_2$ respectively from the horizontal, then answer the following question

If $v_1 = v_2$ and $\theta _1 > \theta _2$, then choose the incorrect statement

A particle is projected from the ground at an angle of $\theta $ with the horizontal with an initial speed of $u$. Time after which velocity vector of the projectile is perpendicular to the initial velocity is

The initial speed of a projectile fired from ground is $u$. At the highest point during its motion, the speed of projectile is $\frac{\sqrt{3}}{2} u$. The time of flight of the projectile is:

A ball is projected from a point $O$ as shown in figure. It will strike the ground after ........ $s$ $\left(g=10 \,m / s ^2\right)$

A ball of mass $160\, g$ is thrown up at an angle of $60^{\circ}$ to the horizontal at a speed of $10 \,m / s$. The angular momentum of the ball at the highest point of the trajectory with respect to the point from which the ball is thrown is nearly $\left(g=10\, m / s ^{2}\right)$ (in $kgm ^{2} / s$)