The probability of choosing at random a number that is divisible by $6$ or $8$ from among $1$ to $90$ is equal to
The probability of choosing at random a number that is divisible by $6$ or $8$ from among $1$ to $90$ is equal to
- A
$\frac{1}{6}$
- B
$\frac{1}{{30}}$
- C
$\frac{{11}}{{80}}$
- D
$\frac{{23}}{{90}}$
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- [KVPY 2011]