The rate constant for a second order reaction is $8 \times {10^{ - 5}}\,{M^{ - 1}}\,mi{n^{ - 1}}$. How long will it take a $ 1\,M $ solution to be reduced to $0.5\, M$

  • A

    $8 \times {10^{ - 5}}\,\min$

  • B

    $8.665 \times {10^3}\,\min$

  • C

    $4 \times {10^{ - 5}}\,\min$

  • D

    $1.25 \times {10^4}\,\min$

Similar Questions

For the reaction $A + B \to C$, it is found that doubling the concentration of $A$ increases the rate by $4$ times, and doubling the concentration of $B$ doubles the reaction rate. What is the overal order of the reaction.

For a reaction $2A + B \to $ Products, doubling the initial concentration of both the reactants increases the rate by a factor of $8$, and doubling the concentration of $+B$  alone doubles the rate. The rate law for the reaction is

The following data are for the decomposition of ammonium nitrate in aqueous solution Volume of ....... The order of the reaction is

${N_2}$ in $cc$ $6.25$ $9.50$ $11.42$ $13.65$ $35.05$
 Time (minutes) $10$ $15$ $20$ $25$ Finally

Assertion :The order of a reaction can have fractional value.

Reason : The order of a reaction cannot be written from balanced equation of a reaction.

  • [AIIMS 2008]

Assertion : The kinetics of the reaction -

$mA + nB + pC \to m' X + n 'Y + p 'Z$

obey the rate expression as $\frac{{dX}}{{dt}} = k{[A]^m}{[B]^n}$.

Reason : The rate of the reaction does not depend upon the concentration of $C$.

  • [AIIMS 2011]