The rate of radioactive disintegration at an | vedclass

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Question

$T _{1 / 2}=\frac{\ln 2}{\lambda}=\frac{0.693}{\lambda}$

$2.2 	imes 10^9=\frac{0.693}{\lambda}$

$\lambda=\frac{0.693}{2.2 	imes 10^9}=3.15 	i

Vedclass · Accepted Answer

$3.17 	imes 10^{19}$

Vedclass · Answer

$T _{1 / 2}=\frac{\ln 2}{\lambda}=\frac{0.693}{\lambda}$

$2.2 	imes 10^9=\frac{0.693}{\lambda}$

$\lambda=\frac{0.693}{2.2 	imes 10^9}=3.15 	imes 10^{-10}$

$R =\lambda N$

$N =\frac{ R }{\lambda}=\frac{10^{10}}{3.15 	imes 10^{-10}}=3.17 	imes 10^{19}$

The rate of radioactive disintegration at an instant for a radioactive sample of half life $2.2 \times 10^9 \;s$ is $10^{10}\; s ^{-1}$. The number of radioactive atoms in that sample at that instant is,

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