The rates of a certain reaction $(dc/dt)$ at different times are as follows

Time                                 Rate (mole $litre^{-1}\,sec^{ -1}$ )

$0$                                        $2.8 \times {10^{ - 2}}$

$10$                                      $2.78 \times {10^{ - 2}}$

$20 $                                     $2.81 \times {10^{ - 2}}$

$30$                                       $2.79 \times {10^{ - 2}}$

The reaction is

  • A

    Zero order

  • B

    First order

  • C

    Second order

  • D

    Third order

Similar Questions

What is the molecularity of the following reaction ?

$1.$ $NH _{4} NO _{2( s )} \rightarrow N _{2( g )}+2 H _{2} O$

$2.$ $2 HI \rightarrow H _{2}+ I _{2}$

$3.$ $2 NO + O _{2} \rightarrow 2 NO _{2}$

The reaction $CH _{3} COF + H _{2} O \quad \rightleftharpoons CH _{3} COOH + HF$

Condition $I$ $:$ $\left[ H _{2} O \right]_{0}=1.00 \,M$

                           $\left[ CH _{3} COF \right]_{0}=0.01 \,M$

Condition $II$ $:$ $\left[ H _{2} O \right]_{0}=0.02 \,M$

                             $\left[ CH _{3} COF \right]_{0}=0.80 \,M$

Condition - $I$ Condition - $II$

Time
$(t)$

$min$

$\left[ CH _{3} COF \right]$ $M$

Time
$(t)$

$min$

$\left[ H _{2} O \right] \,M$
$0$ $0.01000$ $0$ $0.0200$
$10$ $0.00867$ $10$ $0.0176$
$20$ $0.00735$ $20$ $0.0156$
$40$ $0.00540$ $40$ $0.0122$

Determine the order of reaction and calculate rate constant.

Half life of a reaction is found to be inversely proportional to the cube of its initial concentration. The order of reaction is

Reaction : $KCl{O_3} + 6FeS{O_4} + 3{H_2}S{O_4} \to $ $KCl + 3F{e_2}{\left( {S{O_4}} \right)_3} + 3{H_2}O$ 

Which is True $(T)$ and False $(F)$ in the following sentence ?

The order of this reaction is $10$.

The rate of disappearance of $S{O_2}$ in the reaction $2S{O_2} + {O_2} \to 2S{O_3}$ is $1.28 \times {10^{ - 3}}g/sec$ then the rate of formation of $S{O_3}$ is