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2. Electric Potential and Capacitance
medium
The respective radii of the two spheres of a spherical condenser are $12\;cm$ and $9\;cm$. The dielectric constant of the medium between them is $ 6$. The capacity of the condenser will be
A
$240\,pF$
B
$240\,\mu F$
C
$240\,F$
D
None of the above
Solution
(a) $C = 4\pi {\varepsilon _0}K\,\left[ {\frac{{ab}}{{b – a}}} \right] = \frac{1}{{9 \times {{10}^9}}}.6\,\left[ {\frac{{12 \times 9 \times {{10}^{ – 4}}}}{{3 \times {{10}^{ – 2}}}}} \right]$
$ = 24 \times {10^{ – 11}} = 240\,pF$
Standard 12
Physics