Gujarati
6-2.Equilibrium-II (Ionic Equilibrium)
medium

The solubility of $BaS{O_4}$ in water is $2.33 \times {10^{ - 3}}\,gm/litre.$ Its solubility product will be (molecular weight of $BaS{O_4} = 233)$

A

$1 \times {10^{ - 5}}$

B

$1 \times {10^{ - 10}}$

C

$1 \times {10^{ - 15}}$

D

$1 \times {10^{ - 20}}$

(AIIMS-1998)

Solution

(b) The solubility of $BaS{O_4}$ in g/litre is given $2.33 \times {10^{ – 3}}$
in mole/litre.$n = \frac{W}{{m.\,wt}}$$ = 1 \times {10^{ – 5}}$$ = \,\frac{{2.33 \times {{10}^{ – 3}}}}{{233}}$

Because $BaS{O_4}$ is a compound

${K_{sp}} = {S^2} = {[1 \times {10^{ – 5}}]^2}$ $ = 1 \times {10^{ – 10}}$

Standard 11
Chemistry

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