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p-Block Elements - I
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The solubility of anhydrous $AlCl_3$ and hydrous $AlCl_3$ in diethyl ether are $S_1$ and $S_2$ respectively. Then
A
$S_1 = S_2$
B
$S_1 > S_2$
C
$S_1 < S_2$
D
$S_1 < S_1$ but not $S_1 = S_2$
Solution
Anhydrous AlCl3 will dissolve the diethyl ether because anhydrous AlCl3 is a good lewis acid.
It is electron deficient. The lone pairs of diethyl ether will be donated to the anhydrous AlCI3 due to which it is soluble.
On the other hand, hydrous AlCl3 have the water molecules which make it poor lewis acid.
$\mathrm{So}, \mathrm{S}_{1}>\mathrm{S}_{2}$
Standard 11
Chemistry
