Gujarati
6-2.Equilibrium-II (Ionic Equilibrium)
medium

$0.01 \,M$ ${K_2}Cr{O_4}$ में सिल्वर क्रोमेट की विलेयता $2 \times {10^{ - 8}}$ मोल डेसी मीटर$^{ - 3}$ है, तो सिल्वर क्रोमेट का विलेयता गुणनफल होगा

A

$8 \times {10^{ - 24}}$

B

$16 \times {10^{ - 24}}$

C

$1.6 \times {10^{ - 18}}$

D

$16 \times {10^{ - 18}}$

Solution

(d) ${K_{sp}} = {[A{g^ + }]^2}[CrO_4^{ – \, – }] = {[2S]^2}[0.01]$

=$4{S^2}[0.01] = 4{[2 \times {10^{ – 8}}]^2} \times 0.01$$ = \,\,16 \times {10^{ – 18}}$ .

Standard 11
Chemistry

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