- Home
- Standard 11
- Chemistry
6-2.Equilibrium-II (Ionic Equilibrium)
medium
The solubility product of $A{g_2}Cr{O_4}$ is $32 \times {10^{ - 12}}$. What is the concentration of $CrO_4^ - $ ions in that solution
A
$2 \times {10^{ - 4}}\,m/s$
B
$16 \times {10^{ - 4}}\,m/s$
C
$8 \times {10^{ - 4}}\,m/s$
D
$8 \times {10^{ - 8}}\,m/s$
Solution
(a) $\mathop {AgCr{O_4}}\limits_S \to \mathop {2A{g^ + }}\limits_{2S} + \mathop {Cr{O_4}^{ – \,\, – }}\limits_S $
${K_{sp}} = {(2S)^2}S = 4{S^3}$
$S = {\left( {\frac{{{K_{sp}}}}{4}} \right)^{\frac{1}{3}}}$$ = {\left( {\frac{{32 \times {{10}^{ – 12}}}}{4}} \right)^{\frac{1}{3}}}$ $ = 2 \times {10^{ – 4}}$ $M$.
Standard 11
Chemistry
Similar Questions
medium
