- Home
- Standard 11
- Physics
14.Waves and Sound
normal
The speed of sound in oxygen $(O_2)$ at a certain temperature is $460\, ms^{-1}$. The speed of sound in helium $(He)$ at the same temperature will be ............. $\mathrm{m/s}$ (assume both gases to be ideal)
A
$1420$
B
$500$
C
$650$
D
$330$
Solution
Speed of sound is given by : $\mathrm{v}=\sqrt{\frac{\gamma \mathrm{RT}}{\mathrm{M}}}$
$\mathrm{v}_{\mathrm{O}_{2}}=\sqrt{\frac{\frac{7}{5} \mathrm{RT}}{32}}$ and $\mathrm{v}_{\mathrm{He}}=\sqrt{\frac{\frac{5}{3} \mathrm{RT}}{4}}$
$\frac{v_{O_{2}}}{v_{H e}}=\sqrt{\frac{7 \times 3 \times 4}{5 \times 32 \times 5}}$
or $\quad {{\rm{v}}_{{\rm{He}}}} = 460 \times 10 \times \sqrt {\frac{2}{{21}}} \simeq 1420\,\,{\rm{m}}/{\rm{s}}$
Standard 11
Physics
Similar Questions
normal