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4.Average
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The sum of three numbers is $98 .$ If the ratio between first and second be $2: 3$ and between second and third be $5: 8,$ then the second number is
A
$30$
B
$20$
C
$58$
D
$48$
Solution
Let, the numbers be $x, y$ and $z$. Then,
$x+y+z=98, \frac{x}{y}=\frac{2}{3}$ and $\frac{y}{z}=\frac{5}{8}$
$\therefore x=\frac{2 y}{3}$ and $z=\frac{8 y}{5}$
So, $\frac{2 y}{3}+y+\frac{8 y}{5}=98$
$\frac{49 y}{15}=98$ or, $y=30$
Standard 13
Quantitative Aptitude
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