Gujarati
10-2.Transmission of Heat
easy

The temperature gradient in a rod of $0.5 m$ long is ${80^o}C/m$. If the temperature of hotter end of the rod is ${30^o}C$, then the temperature of the cooler end is ...... $^oC$

A

$40$

B

$ - 10$

C

$10$

D

$0$

Solution

(b) $\frac{{{\theta _1} – {\theta _2}}}{l} = 80 \Rightarrow \frac{{30 – {\theta _2}}}{{0.5}} = 80 \Rightarrow {\theta _2} = – {10^o}C$

Standard 11
Physics

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