Gujarati
10-1.Thermometry, Thermal Expansion and Calorimetry
normal

The temperature of a body on Kelvin scale is found to be $X\;K$. When it is measured by a Fahrenheit thermometer, it is found to be ${X^0}F$. Then $X$ is

A

$301.25$

B

$574.25$

C

$313$

D

$40$

Solution

(b) $\frac{{F – 32}}{9} = \frac{{K – 273}}{5} \Rightarrow \frac{{x – 32}}{9} = \frac{{x – 273}}{5} \Rightarrow x = 574.25$

Standard 11
Physics

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