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10-2.Transmission of Heat
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The temperature of hot and cold end of a $20cm$ long rod in thermal steady state are at ${100^o}C$ and ${20^o}C$ respectively. Temperature at the centre of the rod is...... $^oC$
A
$50$
B
$60$
C
$40$
D
$30$
Solution
(b) Temperature gradient $ = \frac{{100 – 20}}{{20}} = 4^\circ C/cm$
temperature at centre $ = 100 – 4 \times 10$ = $ 60°C$
Standard 11
Physics
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