10-2.Transmission of Heat
medium

The temperature of hot and cold end of a $20cm$ long rod in thermal steady state are at ${100^o}C$ and ${20^o}C$ respectively. Temperature at the centre of the rod is...... $^oC$

A

$50$

B

$60$

C

$40$

D

$30$

Solution

(b) Temperature gradient $ = \frac{{100 – 20}}{{20}} = 4^\circ C/cm$

temperature at centre $ = 100 – 4 \times 10$ = $ 60°C$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.