10-1.Thermometry, Thermal Expansion and Calorimetry
easy

The thermal capacity of $100 \,g$ of aluminum (specific heat $=0.2 \,cal / g ^{\circ} C$ ) is ............ $cal / ^{\circ} C$

A

$0.002$

B

$20$

C

$200$

D

$100$

Solution

(b)

$\text { Thermal capacity }= m \cdot C$

$=100 \times 0.2=20 \,cal /{ }^{\circ} C$

Standard 11
Physics

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