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10-1.Thermometry, Thermal Expansion and Calorimetry
easy
The thermal capacity of $100 \,g$ of aluminum (specific heat $=0.2 \,cal / g ^{\circ} C$ ) is ............ $cal / ^{\circ} C$
A
$0.002$
B
$20$
C
$200$
D
$100$
Solution
(b)
$\text { Thermal capacity }= m \cdot C$
$=100 \times 0.2=20 \,cal /{ }^{\circ} C$
Standard 11
Physics