The thermal capacity of a body is $80\, cal$, then its water equivalent is
$80 \,cal / gm$
$8\, gm$
$80 \,gm$
$80 \,kg$
A 'thermacole' icebox is a cheap and an efficient method for storing small quantities of cooked food in summer in particular. A cubical icebox of side $30 \,cm$ has a thickness of $5.0\; cm .$ If $4.0\; kg$ of ice is put in the box, estimate the amount of ice (in $kg$) remaining after $6 \;h$. The outside temperature is $45\,^{\circ} C ,$ and co-efficient of thermal conductivity of thermacole is $0.01\; J s ^{-1} m ^{-1} K ^{-1} .$ Heat of fuston of water $=335 \times 10^{3}\;J kg ^{-1} $
$5\,\,gm.$ of ice at $0\,^oC$ is dropped in a beaker containing $20\,\,gm.$ of water at $40\,^oC.$ The final temperature will be ........ $^oC$
$5\, g$ of ice at $0°C$ is dropped in a beaker containing $20\, g$ of water at $40°C.$ The final temperature will be........ $^oC$
Calorie is defined as the amount of heat required to raise temperature of $1g$ of water by $1°C$ and it is defined under which of the following conditions
A piece of ice falls from a height $h$ so that it melts completely. Only one-quarter of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of $h$ is
[Latent heat of ice is $3.4 \times 10^{5}\; J / k g$ and $g=10\; N / kg ]$