The time dependence of a physical quantity $P$ is given by $P\, = \,{P_0}\,{e^{ - \alpha {t^2}}}$ where $\alpha $ is a constant and $t$ is the time then constant $\alpha $ is
The time dependence of a physical quantity $P$ is given by $P\, = \,{P_0}\,{e^{ - \alpha {t^2}}}$ where $\alpha $ is a constant and $t$ is the time then constant $\alpha $ is
- A
Dimension less
- B
Dimensions of $T^{-2}$
- C
Dimensions of $P$
- D
Dimensions of $T^2$
Similar Questions
$\left(P+\frac{a}{V^2}\right)(V-b)=R T$ represents the equation of state of some gases. Where $P$ is the pressure, $V$ is the volume, $T$ is the temperature and $a, b, R$ are the constants. The physical quantity, which has dimensional formula as that of $\frac{b^2}{a}$, will be
$\left(P+\frac{a}{V^2}\right)(V-b)=R T$ represents the equation of state of some gases. Where $P$ is the pressure, $V$ is the volume, $T$ is the temperature and $a, b, R$ are the constants. The physical quantity, which has dimensional formula as that of $\frac{b^2}{a}$, will be
- [JEE MAIN 2023]
Which of the following units denotes the dimensions $\frac{{M{L^2}}}{{{Q^2}}}$, where $Q$
denotes the electric charge?
Which of the following units denotes the dimensions $\frac{{M{L^2}}}{{{Q^2}}}$, where $Q$
denotes the electric charge?
If velocity $v$, acceleration $A$ and force $F$ are chosen as fundamental quantities, then the dimensional formula of angular momentum in terms of $v,\,A$ and $F$ would be
If velocity $v$, acceleration $A$ and force $F$ are chosen as fundamental quantities, then the dimensional formula of angular momentum in terms of $v,\,A$ and $F$ would be
Dimension of $\frac{1}{\mu_0 \varepsilon_0}$ should be equal to
Dimension of $\frac{1}{\mu_0 \varepsilon_0}$ should be equal to
- [JEE MAIN 2023]
The physical quantity that has no dimensions
The physical quantity that has no dimensions