Time period of a simple pendulum is 2, sec . If its length is increased 4 times, then its period bec

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13.Oscillations

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The time period of a simple pendulum is $2\, sec$. If its length is increased $4$ times, then its period becomes ..... $\sec$

A

$16$

B

$12$

C

$8$

D

$4$

(AIPMT-1999)

Solution

(d) $T \propto \sqrt l $

==> $\frac{{{T_1}}}{{{T_2}}} = \sqrt {\frac{{{l_1}}}{{{l_2}}}} $

==> $\frac{2}{{{T_2}}} = \sqrt {\frac{l}{{4l}}} $

==> ${T_2} = 4\,sec$

Standard 11

Physics

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